Given $y>0$ I want to find least $\alpha\geq1$ and regions of $m$ and $x$ that satisfies $$y^{x}\leq m^\alpha$$ $$m\leq\frac{(1-3x)\log y}{4\log(1-3x)-4\log 2+4\log\log y}$$
$$1+\frac1{x}\leq m$$
How can this be done?
Given $y>0$ I want to find least $\alpha\geq1$ and regions of $m$ and $x$ that satisfies $$y^{x}\leq m^\alpha$$ $$m\leq\frac{(1-3x)\log y}{4\log(1-3x)-4\log 2+4\log\log y}$$
$$1+\frac1{x}\leq m$$
How can this be done?
Copyright © 2021 JogjaFile Inc.