Is there any way I can solve the following recursion function?
$$f(n) = \binom{f(n-1)}{2}$$
Or can be written as $$f(n) = 1/2(f(n-1)(f(n-1) - 1))$$
f(0) = 4, f(1) = 6, f(2) = 15, ...
2026-04-08 07:27:54.1775633274
Is there a generalized formula for recusive Binomial coefficient?
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It’s OEIS A086714, and it grows very rapidly. The OEIS entry does not have a closed form, but it does offer the limit
$$\lim_{n\to\infty}f(n)^{1/2^{n+1}}=1.280497808541657066685323460209089278782...$$