Given a pyramid $T.ABCD$ where $ABCD$ is a square. See the following figure.
$L$ and $K$ are midpoints of $TA$ and $TC$ respectively. The line intersecting plane $TBD$ and $BKL$ is need to draw.
My attempt
$B$ is one common point shared between the planes in question. We need one more common point to draw the required intersecting line. Using symmetric, the midpoint of $LK$ (denoted as $M$ in the following figure) is the second common point. As a result, $BM$ is the intersecting line.
Question
Is there any other method (maybe without using symmetric) to draw the line?

