Is there any special function that can be related to a generalized falling factorial as the gamma function relates to the ordinary falling factorial?

124 Views Asked by At

The falling factorial can be shown to be related to the gamma function according to: $(x)_n = \frac{\Gamma(x+1)}{\Gamma(x-n+1)}$.

Consider a generalized falling factorial of the form: $(x)_{n\lambda}=x(x-\lambda)(x-2\lambda)...(x-(n-1)\lambda)$, where $\lambda$ is not a constant that can be factored out.

Question: Is there any modified ("gamma") function that produce similar relationship as that between the ordinary falling factorial and gamma function? Please, notice that the problem doesn't reduce to: $(x)_{n\lambda}=\lambda^{n}(\frac{x}{\lambda})_n $

1

There are 1 best solutions below

6
On

Letting

$$A_k(n) = \int_{0}^\infty \frac{1}{k} e^{-x/k} x^{n/k} \, dx$$

we see, by integration by parts, that

$$A_k(n) = n A_k(n-k)$$

and furthermore $A_k(0) = 1$.

Therefore, for $n$ a multiple of $k$, we see by induction that $$A_k(n) = n \cdot (n-k) \cdot (n-2k) \cdot \cdots \cdot 1$$

and so:

$$n \cdot (n-k) \cdot (n-2k) \cdot \cdots \cdot (n-(i-1)k) = A_k(n) / A_k(n-ik).$$

In fact this holds for $n$ not a multiple of $k$ as well.