Is this octogon topologically equivalent to the Klein Bottle?

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Note: this is an extension of a previous problem (identify the topological type obtained by gluing sides of the hexagon ) where a hexagon was considered.


Is the space below also a Klein bottle ($d$ and $e$ have no direction)?

Surface 2

I know that if the black lines, $d$ and $e$, were removed then we would have a Klein bottle as it would reduce to this:

Klein bottle

But do the black lines stop it from being topologically equivalent to a Klein bottle, and if so, how?

Thank you