Formula I found online:
$$V_{GWS} = \frac{1}{2\Omega\sin(lat)} \cdot \frac{1}{\rho} \cdot \frac{\Delta p}{d}$$
Here is my problem:
My solution: $$V_{GWS} = \frac{1}{14.6\cdot10^{-5}\cdot(-0.43)} \cdot \frac{1}{0.70} \cdot \frac{800}{400000} \frac{\text{Pa}}{\text{m}}= -4.55$$
Wind speed shouldn't be negative, right? So something seems off. Would greatly appreciate the help. Am confused at what direction the wind would be moving too.
Thank you
$\sin(35\,\text{rad})=-0.4282$ but $\sin(35°)=0.5736$. Everything else is OK. Put your calculator in degrees mode!
Oh yes, wind flows counterclockwise around a low pressure center in the northern hemisphere so along an isobar to the northeast.