Is $x=-2n$ the solution of :$ \operatorname{erf}(1-x) +\zeta(x)=1$ with $n$ is a positive integer?

Question

let $x$ be a real number , I want to know if $x=-2n$ with $n$ is a positive integer is a solution of this equation:$$ \operatorname{erf}(1-x) +\zeta(x)=1$$ as shown here by wolfram alpha , however wolfram alpha gaves us a real solution which is :$1.87...$, then I'm very interesting to know how the titled equation could be solved using any represenation of zeta and erf functions ?