I have come across a stage of the proof:
$$ \left(x+\frac b{2a}\right)^2=\frac{b^2-4ac}{4a^2}$$
How does $\left(x+\frac b{2a}\right)^2$ not equal $\pm x\pm \frac b{2a}$ when taking the square root?
2026-04-01 04:21:57.1775017317
Issue on proving quadratic formula
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Because $\sqrt{\left(x+\frac b{2a}\right)^2} =\left(x+\frac b{2a}\right) \text{ or } -\left(x+\frac b{2a}\right) $. Both $x$ and $\frac{b}{2a}$ must have the same signs.