I want to find the laplace of 1/rootcos(t)
Laplace calculators don't give an answer with this as an input. I know nothing about laplace, so can someone explain why this happens? Is it impossible to perform laplace on square roots? I'm assuming there's nothing wrong with the calculators.
In case you want a nice formula (given by a CAS, be sure !) $$\mathcal{L}_t\left[\frac{1}{\sqrt{\cos(t)}}\right](s)=\Gamma \left(\frac{2i s+1}{4}\right) \left(i \, _2\tilde{F}_1\left(1,\frac{2 i s+3}{4} ;\frac{2 i s+3}{4} ;-1\right)+\frac{\left(1-i\right) \sqrt{\pi } e^{\frac{3 \pi s}{2}} (\coth (\pi s)-1)}{2\,\Gamma \left(\frac{2i s+3}{4}\right)}\right)$$