The numbers n such that $\binom{n}{1}$ have $1$ prime factor (counted with multiplicity) are simply the primes. Therefore, for $k=1$ this gives the largest known prime, $n=2^{82589933}-1$. For $k=2$, the numbers n such that $\binom{n}{2}$ have $2$ prime factors (counted with multiplicity) are $2p$ such that $p$ and $2p-1$ are primes and the safe primes, primes $p$ such that $(p-1)/2$ is also prime. Since $2618163402417\cdot2^{1290001}-1$, the largest known prime $p$ such that $(p-1)/2$ is also prime, is greater than $7775705415\cdot2^{175116}+2=2p$, where $p$ is the largest known prime such that $2p-1$ is also prime, $2618163402417\cdot2^{1290001}-1$ is the largest known such $n$ for $k=2$. This will change from time to time.
What about $3\le k \le 32$?
For $3\le k\le 14$, I found in OEIS that $\binom{2918756139031688155200+k}{k}$, where $n=2918756139031688155200+k$, $k\le 14$, and $\binom{7272877497848202239}{k}$, where $n=7272877497848202239$, $k\le 14$, have k prime factors (counted with multiplicity). These are just the lower bounds for such $n$'s. Definitely these aren't the largest known $n$'s such that $\binom{n}{k}$ has $k$ prime factors (counted with multiplicity) for $3\le k \le6$.
Main problem: Find at least one positive integer $n\gt10^4$ such that $\binom{n}{k}$ has exactly $k$ prime factors (counting multiplicity) for each $15\le k\le 32$.
This is a partial answer. As above mentioned, those values are probably much too small. The table (created with the free calculator PARI/GP) lists the largest solution $n\le 3\cdot 10^5$ for $k=3,\cdots ,32$ :
For small $k$ , we can find at least lower bounds for the desired values. Define $n(k)$ to be the largest known $n$ for the corresponding $k$ , we can say $$n(3)\ge 10^{1000}+1401064021050844540399$$ $$n(4)\ge 10^{200}+6985786741233199$$ $$n(5)\ge lcm([1..200])\cdot 5012200-1$$ $$n(6)\ge lcm([1..200])\cdot 5012200-1$$ $$n(7)\ge lcm([1..80])\cdot 15688070-1$$ $$n(8)\ge lcm([1..80])\cdot 15688070-1$$ $$n(9)\ge lcm([1..35])\cdot 160479169-1$$ $$n(10)\ge 101114034374873519$$ With increasing $k$ , it will become more and more difficult to find huge examples. Everyone finding larger examples can edit the question accordingly.