as you can see i would like to expand in a Taylor-Laurent around 0 the function in the title. I can kinda see that it should be an essential singularity, because it should be for ${\exp (1/z)}$ and for $\frac {1}{1-\sin(1/z)}$. However i don't figure out how to expand each term in a Laurent series, to prove that is an essential singularity by seeing that the negative powers are infinite. Is the Laurent series expansion around $0$ even possible? I thought it always was even for essential singularities.
2026-03-27 23:35:27.1774654527
Laurent series of $f(z)=\frac {\exp (1/z)}{1-\sin(1/z)}$ around 0.
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