What is the length of the arc? $$ y = +\sqrt\frac{x^3 -4x^2 +4x}{6} $$ from $x = 2 $ to $ x =8$
I used the equation $$ L(x) = \int_{x_1}^{x_2} \sqrt{1+ (y')^2} dx$$ where my $ x_1 = 2$ and $x_2 = 8 $. My final answer is approximately 9.2. Is this correct?