I was thinking to go this way:
Determine if $A$ is positive definite, if each of the eigenvalues of $A$ are positive. Then we diagonalize $A$. $A=PDP^T$. Thus we can let $C$ be the diagonal matrix whose diagonal entry is $√λ$. Thus $CC = D$ Now let $B = PCP^T$, and it remains to show that $B^TB = A$.
Any thoughts?