Let $γ$ be a counter-clockwise path around the unit circle centred at zero. Compute the path integral$\int \frac{(z+1)^{2020}}{z}dz$

Question

$\int \frac{(z+1)^{2020}}{z}dz$

My solution :

The path is a closed circle of centre $a = 0$ , radius, $ r=1$ so $ C(a,r) = C(0,1)$ so using Cauchy's integral formula, let $f(z) = (z+1)^{2020}$ and $\frac {1}{(z-w)} = 1/z \implies w= 0$ hence solution is

$2\pi if(0) = 2\pi i (1) ^{2020} = 2\pi i $

Is my solution correct?