I found this result stated without explanation in the proof for Chebyshev inequality but the result is unintuitive to me.
2026-03-26 04:32:01.1774499521
Let $X$ be a random variable. Then for $c>0$, how is $Pr(|X-E(X)|\geq c)=Pr(|X-E(X)|^2\geq c^2)$?
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