Let X be the number of times you and your friend get the same outcome. Then X is distributed as

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You and your friend have a fair coin each. Both of you toss the coins simultaneously, record the outcomes, and repeat the process, for a total of $n$ times. Let $X$ be the number of times you and your friend get the same outcome. Then $X$ is distributed as

SELECT ALL CORRECT OPTIONS

(a) $Binom(n,1/2)$

(b) $Geom(1/2)$

(c) $Binom(n,3/4)$

(d) $Binom(n,1/4)$

I thought the answer as $Binom(n,1/2)$ .. Since getting the same number of outcome is equiprobable. Please correct me if I am wrong.

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You and your friend have a fair coin each. Both of you toss the coins simultaneously, record the outcomes, and repeat the process, for a total of $n$ times. Let $X$ be the number of times you and your friend get the same outcome. Then $X$ is distributed as

Suppose that $X$ is random binomial variable. We have $X \sim Bin(n,p)$ which describes the number of successes $k$ in $n$ independent trials.

The question asks that both of toss the same outcome. The sample space for the tosses for both of you are given by

$$\Omega = \{ (H,H), (H,T) ,(T,H), (T,T)\} $$

the outcomes where they are the same is simply

$$E =\{ (H,H) ,(T,T)\} $$ the probability $p$ is $\frac{2}{4} =\frac{1}{2}$

Then we see that $X \sim Bin(n,\frac{1}{2})$. The geometric distribution is also constructed from independent bernoulli trials, however it is describing until you don't succeed.