$E[X(t)]$=
$E[Y1+Y2+⋯+Yt]$ =
$E[Y1]+E[Y2]+⋯+E[Yt]$ = 0.
Then I got stuck trying to find Rx(n, m) of X(t) process. I'm still learning random processes, am I right in saying it's a wide-sense stationary process due to E[X(t)] = 0? Then,
$Rx(n,m) = (Cov(X(n),X(m)) = E[X(n)X(m)]$ =
$E[X(n)(X(n) + Yn+1 +Yn+2 +⋯ + Ym)]$ =
$E[X(n)^2] + E[X(n)]E[Yn+1 + Yn+2 + ⋯ + Ym]$ =
$E[X(n)^2]$.
Is this correct? If not, where did it go wrong?