$$\lim_{x\to2}{\frac{\sqrt{3x-2}-\sqrt{5x-6}}{\sqrt{2x-1}-\sqrt{x+1}}}$$
Evaluate the limit.
Thanks for any help
$$\lim_{x\to2}{\frac{\sqrt{3x-2}-\sqrt{5x-6}}{\sqrt{2x-1}-\sqrt{x+1}}}=\lim_{x\to2}{\frac{(3x-2-(5x-6))(\sqrt{2x-1}+\sqrt{x+1})}{(2x-1-(x+1))(\sqrt{3x-2}+\sqrt{5x-6})}}=$$ $$=-2\cdot\frac{\sqrt3+\sqrt3}{2+2}=-\sqrt3$$
That stinks a lot as homework. A general hint for solving such a problem is to "rationalize" both numerator and denominator i.e. multiply the whole thing by
$$\frac{\sqrt{3x-2}+\sqrt{5x-6}}{\sqrt{3x-2}+\sqrt{5x-6}}\cdot \frac{\sqrt{2x-1}+\sqrt{x+1}}{\sqrt{2x-1}+\sqrt{x+1}}$$
Hint:
Set $x-2=h$
and rationalize the denominator & the numerator.
Setting limit to $0$ often eases of the calculation
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$$\lim_{x\to2}{\frac{\sqrt{3x-2}-\sqrt{5x-6}}{\sqrt{2x-1}-\sqrt{x+1}}}=\lim_{x\to2}{\frac{(3x-2-(5x-6))(\sqrt{2x-1}+\sqrt{x+1})}{(2x-1-(x+1))(\sqrt{3x-2}+\sqrt{5x-6})}}=$$ $$=-2\cdot\frac{\sqrt3+\sqrt3}{2+2}=-\sqrt3$$