Hi i have worked out the answers for this question which is (3,-5,1). Is there any ways to check whether my answers are correct ? Thanks in advance :)
2026-04-29 14:19:05.1777472345
Linear Algebra , Geometry
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From $ \vec{x}=(1,1,1)^T+t(2,1,-1)^T$ and $x=5$, we get $5=1+2t$, hence $t=2.$ This gives $y=3$ and $z=-1.$ Therefore the point of intersectioin is
$$(5,3,-1).$$