Linearise equation. Solving for x

Question

$$y = 2480.1 \times e^{-0.057 x}$$

Looking to get this equation in terms of x. Thought it was ((log y)/log 2480.1))/(-0.057)=x But not giving me answer expected for x. Thanks

Answer 1

Your question provides you with $y = 2480.1e^{−0.057x}$. Thus, step by step as follows, we have: $$\frac{y}{2480.1} = e^{−0.057x}$$ $$ln({\frac{y}{2480.1}}) = −0.057x$$ $$x = -\frac{1}{0.057} \cdot ln({\frac{y}{2480.1}})$$