Locus of points $r$ such that $|r-p| - |r-q| = K$ for some constant $K$ and for fixed points $p$ and $q$

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Label the points of a triangle $p$, $q$, $r$ in $\mathbb{R}^2$.

Fixing both $p$ and $q$, I need to find the locus of points $r$ such that $$|r-p| - |r-q| = K$$ for some real number $K > 0$

Letting $q = (-c, 0)$, $p = (c, 0)$, $r = (r_1, r_2)$ for some $c > 0$. Then the problem becomes $$\sqrt{(r_1 - c)^2 + r_2^2} - \sqrt{(r_1 + c)^2 + r_2^2} = K$$

By solving this the above should follow, but from here all roads I try are dead-ends. Is there a known solution to such a problem?

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The locus of such points whose difference of distances to 2 fixed points $p$ and $q$ is a branch of a hyperbola with foci $p,q$.

As $K>0$, $|r-p| > |r-q|$ : therefore, it is the branch which is closest to focus $q$.

See this ; unfortunately no difference of treatment is made there between the two branches.