Can anyone explain how this identity results in the RHS?
Thank you
You need to know that $$\log_b m^n=n\log_b m.$$
This is true since we have that $$m^n=(b^{\log_b m})^n=b^{n\log_b m}.$$
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You need to know that $$\log_b m^n=n\log_b m.$$
This is true since we have that $$m^n=(b^{\log_b m})^n=b^{n\log_b m}.$$