Markov blanket and Conditional independence

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$X$ --> $Z$ <-- $Y$

When using Bayes ball to check the independence of $X$ and $Y$ given $Z$, it is known that $P(X,Y|Z)\neq P(X|Z)P(Y|Z)$ in the above graph.

(There is an example to help you to understand why. Considering that

  • $X$: I am kidnapped.
  • $Y$: I am sick.
  • $Z$: I am late for the meeting.

I am late may be because of $X$ or $Y$. If you see me that I am late for the meeting and I am sick. Then $P(X|Z,Y)\ll P(X|Z)$. )

My question is:

There is another rule called Markov Blanket, which states that given the Markov blanket $B(X)$ of $X$, $X$ is conditional independent with others $\neg X$ given $B(X)$.

$B(X)$ is composed of $X$'s parents, children, children's parents.

In the above graph, $B(X)=\{Z\}$, however, as I stated before, $X\not\perp Y|Z$.

So, what's wrong?

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In the Markov Blanket of X you are forgetting that Y should also be included. Y is one of X's children's parents (otherwise known as one of X's co-parents). So B(X) includes both Z and Y.