Given the matrix $A∈M_2(\mathbb{Z_7})$
$$ \begin{bmatrix} 1 & 2 \\ 2 & 5 \\ \end{bmatrix} $$
Is it diagonalizable? I think it is because I calculated the eigenvalues which are $4$ and $2$. Since the eigenvalues are two and the order of the matrix is two then the matrix is diagonalizable, right?
Yes, your argument is correct. Perhaps that this will sound pedantic, but you could also have added that, in $\mathbb{Z}_7$, $4\neq2$. That is, you found two distinct eigenvalues,