$$\begin{bmatrix} (V_1 \bullet V_1) & (V_2 \bullet V_1)\\ (V_1 \bullet V_2) &(V_2 \bullet V_2) \\ \end{bmatrix} = \begin{bmatrix} V_1\\ V_2\\ \end{bmatrix} \cdot \begin{bmatrix} V_1^T &V_2^T\end{bmatrix} $$
I need to show that this equality is true. So far I tried taking the determinant of each side but I don't know how to relate the two to show the equality holds. Any help would be appreciated.
My answer is based on the assumption that we are dealing with row vectors. Then the right side is simply:
$\begin{pmatrix} V_1V_1^T & V_1V_2^T \\ V_2V_1^T & V_2V_2^T \end {pmatrix} $
which is precisely equal to the left side given the definition of a dot product in Euclidean space.