How do I find a,b,c and d in this matrix equation? $$ \begin{bmatrix} 3 & 2a \\ b & -2 \\ \end{bmatrix} + \begin{bmatrix} b & -a \\ c & d \\ \end{bmatrix} = \begin{bmatrix} a & 2 \\ 2 & 6 \\ \end{bmatrix} $$
So far, I've worked out $d$ by using doing 6-(-2) which equals to 8. I'm not so sure on how to work out the rest.
Adding each component: $$3+b=a$$ $$2a-a=2$$ $$b+c=2$$ $$-2+d=6$$ I'm sure you can work out the rest.