Solving matrix equation $A^2X-B^T = 3X$ (to find X), I'm trying to do next thing:
$A^2X-B^T = 3X$
$A^2X-3X = B^T$
$(A^2-3)X = B^T$
Can we do it in that way and, if yes, what should we do with $(A^2 - 3)$?
Thank you in advance!
2026-03-28 22:37:16.1774737436
Matrix equation with several X
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$$X = (A^2-3I)^{-1}B^T$$ If we assume that this matrix is invertible. Even if it is not, you may still be in the case that you have an underdetermined system, then you simply have infinitely many solutions. In the case where you have an overdetermined system you can use least squares.