I'm going through the proof for the Orthogonal Procrustes problem and I wanted to see how they got the following relation.
$$\langle \Omega A - B, \Omega A - B \rangle = ||A||^2_F+||B||^2_F-2\langle\Omega A, B\rangle$$
After using inner product rules, I arrived at the following quantity
$$\langle \Omega A, \Omega A\rangle + \langle B, B \rangle - 2 \langle \Omega A, B \rangle$$
which gives me
$$||\Omega A||_F + ||B||_F -2\langle\Omega A, B \rangle$$
which is wrong because of the extra $\Omega$. I'm not sure if there's a way to simplify beyond this, or if this is just wrong. It might help to know that $\Omega$ is an orthogonal matrix, since $||\Omega||_F = n$ if $\Omega$ is an $n \times n$ matrix.
I'm thinking that since $||\Omega A||_F = n||A||_F$, the $ \underset{\Omega}{\text{arg min}}$ doesn't change regardless of constant $n$.
For unitary $\Omega$ $$\langle \Omega A - B, \Omega A - B \rangle=\langle \Omega A , \Omega A\rangle-2\langle \Omega A,B \rangle+\langle B, B \rangle$$ Also $$< \Omega A,\Omega A>=trA^H\Omega^H\Omega A=trA^HA=<A,A>$$which completes our proof