Consider
$$X = \begin{bmatrix} 7 & 10 \\ 15 & 22 \end{bmatrix}.$$
Find a real matrix $A$ for which $A^2 = X$. I don't know how to answer this or where to start.
Consider
$$X = \begin{bmatrix} 7 & 10 \\ 15 & 22 \end{bmatrix}.$$
Find a real matrix $A$ for which $A^2 = X$. I don't know how to answer this or where to start.
On
A surprising result is that the square root of a 2 x 2 matrix can be constructed, it is not unique, and since it involves two very relevant functions of a matrix I think it's worth presenting : $$ M=\begin{bmatrix} a & b \\ c & d \end{bmatrix}$$
Let $ a + d = tr(M) $ , $ ad - bc = Det M $
$ s^2 = Det M $ , $ t^2 = tr(M) + 2s $
Then $ R = \frac{1}{t}\begin{bmatrix} a+s & b \\ c & d+s \end{bmatrix} $ is a square root of the matrix M.
See: http://en.wikipedia.org/wiki/Square_root_of_a_2_by_2_matrix
Write
$$A=\begin{bmatrix} a & b \\ c & d \end{bmatrix}.$$
Then
$$A^2=\begin{bmatrix} a^2+bc & \cdot \\ \cdot & \cdot \end{bmatrix}.$$
I'll let you work out the expressions that should go into the dots inside the matrix. Then solve for $a,b,c,d$.