Find the maximum value of coefficient in the expansion of $(x+y+z+w)^{25}$.
Basically what the question is saying is that all term will be of type $k x^{r_1}y^{r_2}z^{r_3}w^{r_4}$ so what can be maximum value of $k$.
Well in binomial expansion, middle binomial coefficients are greatest but how to expand that thought here?
I wrote it as $(a+b)^{25}$, in this expansion the term having greatest coefficient will be $C(25,13) (x+y)^{12}(z+w)^{13}$ and then take maximum binomial coefficient of $(x+y)^{12}(z+w)^{13}$ to get answer as $C(25,13) \times C(12,6) \times C(13,7)$ but I am not sure it is correct. Could someone help me with this?
Your observation that in binomial coefficients, the central ones are largest is the key. Let's conjecture that the same holds here: the multinomial coefficient will be largest when the difference between any two of the $r_i$ is at most $1$. To prove this, suppose for example $r_1-r_2\geq2.$ Show that you get a larger coefficient if you replace $r_1$ by $r_1+1$ and $r_2$ by $r_2-1,$ leaving $r_3,r_4$ unchanged. This follows at once from your observation about the binomial coefficients.