maximum volume of a box inside an ellipsoid

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What is the maximum volume of a box that can be placed inside an ellipsoid $\frac{x^2}{16}+\frac{y^2}{9}+\frac{z^2}{25}=1$

The volume of a box is $V=xyz$ so I need to find $x,y,z$ with respect to the ellipsoid conditions and then find the maximum point.

$x=\sqrt{16-\frac{16y^2}{9}-\frac{16z^2}{25}}$

$y=\sqrt{9-\frac{9x^2}{16}-\frac{9z^2}{25}}$

$z=\sqrt{25-\frac{25x^2}{16}-\frac{25y^2}{9}}$

We take only the positive root as the length but on the other hand a negative root is just a length to the other direction and if 2 of the variables are negative the volume will be still a positive number

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One simple standard procedure would be when you have the condition:

$$f(x,y,z)=\frac{x^2}{16}+\frac{y^2}{9}+\frac{z^2}{25}=1$$

and you want to maximize

$$V(x,y,z)=xyz$$

to set $$\vec\nabla f(x,y,z)=\lambda\cdot\vec\nabla V(x,y,z)$$

their gradient looking in the same direction. After that you have to choose the maxima out of the extrema.

This is the geometric approach learned in my analyses course.