mean of two consecutive number helps proving both number equals..

Question

Well I was wondering how is this possible.

let say:

4=4

-> R.H.S

$=4-(9/2)+(9/2)$

$=\sqrt{ (4 - ( 9/2 )) ^ 2}+ (9/2)$

$=\sqrt{ 16 - 36 +( 9/2 )^2}+ (9/2)$

$=\sqrt{ - 20 +( 9/2 )^2}+ (9/2)$

$=\sqrt{ -45 + 25 +( 9/2 )^2}+ (9/2)$

$=\sqrt{ 5^2 - 2x(9/2)x5 +( 9/2 )^2 }+ (9/2)$

$=\sqrt{ (5 - (9/2))^2 }+ (9/2)$

$=5- (9/2) + (9/2)$

=5

going through this I found that every number can be proven equal to any number?????? still scratching my head.....

Answer 1

This is old.

$$x \ne \sqrt{x^2} = |x|$$

for $x < 0$.