Minimal polynomial substitution

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This is probably a very easy question, I'm just not strong at the concept.

Let $ A $ be an $ n \times n $ matrix with coefficient in a field $ F $. Then $ A $ determines a linear map $ T: F^n \to F^n $ and gives $ F^n $ a $ F[x] $-module. The characteristic polynomial of $ A $ is $ \text{det}(xI - A) $, while the minimal polynomial is defined to be the monic polynomial generating $ \text{Ann}(F^n) $ as the above $ F[x] $-module.

When finding the invariant factors, the method I see is to calculate the minimal polynomial by using the determinant formula. For example, say it is $ (x-2)^2(x-3) $. Now the minimal polynomial is either $ (x-2)(x-3) $ or $ (x-2)^2(x-3) $. But in the next step, the book substitutes in $ (A- 2I)(A-3I) $ and check if it's zero. Why is this possible? This looks like the Cayley-Hamilton theorem, but isn't that only for characteristic polynomials?

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This is the most convenient way. The minimal polynomial is the monic polynomial of minimum degree (on the given field) which vanishes at the endomorphism ($A$ in your example). Certainly the polynomial you found (the characterisic one) vanishes at $A$ but you don't know if it is also the minimal polynomial, so you must check if its proper divisors (with all irreducible factors) vanish at the matrix.