Minimum length of axes intercept of a line passing through a fixed point

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I encountered this problem:

A straight line passes through a fixed point $(h,k) \ (h,k>0)$ and intersects the coordinate axes at $P(a,0)$ and $Q(0,b)$. Show that the minimum length of $PQ$ is $(h^{2/3}+k^{2/3})^{3/2}$.

Now, I proceeded like this:

If a line passes through $(h,k)$ then its equation is $$\frac{y-k}{x-h}=m.$$

If it passes through $(a,0)$ and $(0,b)$ then we have $a=h-\frac{k}{m}$ and $b=k+mh$.

Length of $PQ$ is $\sqrt{a^2+b^2}$.

We can put the value of $a$ and $b$ in the expression and then differentiate w.r.t. $m$, to find out the minimum value.

But after equating the first differential to $0$, I found two roots of $m$. As the values of $h$ and $k$ can be positive or negative, I cannot put them in the second differential to find out which one is minimum and which one is maximum.

What am I doing wrong? and, Is there any other, simpler method that can be used?

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Equation of line $\mathcal{AB}$ is $\displaystyle \frac{x}{a}+\frac{y}{b} =1$

Line passes through fixed point $(h,k)$

Then $\displaystyle \frac{h}{a}+\frac{k}{b} =1$

Use Holder,s Inequality

$$(a^2+b^2)\bigg(\frac{h}{a}+\frac{k}{b}\bigg)\bigg( \frac{h}{a}+\frac{k}{b}\bigg)\geq \bigg(h^{\frac{2}{3}}+k^{\frac{2}{3}}\bigg)^3$$

$$\mathcal{\min{PQ}}=\sqrt{a^2+b^2}\geq \bigg(h^{\frac{2}{3}}+k^{\frac{2}{3}}\bigg)^{\frac{3}{2}}$$