Minimum of Super Martingale and a Constant is Still a Super Martingale

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I am having trouble proving the following statement:

Let $\alpha>0$ and $M:\Omega\times [0,1]\longrightarrow \mathbb{R}$ be a super martingale. Then $M\wedge \alpha$ is also a super martingale.

The adaptedness/measurability and the integrability requirements are easy. But I am struggling to show that

\begin{equation*} \mathbb{E}[M_t\wedge \alpha | \mathscr{F}_s] \le M_s\wedge \alpha \qquad \forall s<t \end{equation*}

Any help would be greatly appreciated! Thanks in advanced