Mittag-Leffler Theorem Exercise - Find Sum of Series

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The exercise asks to find the closed form of $$\sum_{n=-\infty}^{\infty}\frac{1}{(z+n)^2+a^2}$$where $a$ is a complex number.

I know that $\frac{\pi^2}{\sin^2(\pi z)}=\sum_{n=-\infty}^{\infty}\frac{1}{(z+n)^2}$, but don't how to develop this fact. Is this some kind of a shift of this series?

Thank you!