Two players call the number 1,2 or 3. If the sum of the named numbers does not exceed 4, then everyone gets what he asked for. If the sum is strictly greater than 4, everyone gets 0.
Let p1,p2,p3 be the mixed strategy of the second player. What is the expected payoff of the first player from applying the pure strategy that player always calls 1
Could someone check my solution?
My solution is p1*p1 since then he will get 1.