I have found that if,
a ≡ b (mod m)
then
b ≡ a (mod m)
The meaning of a ≡ b (mod m) is that m | (a-b) & the meaning of b ≡ a (mod m) is that m | (b-a) but , (a-b) is opposite to (b-a) So , are we taking only the absolute value of the differences between a & b when we are dealing with congruence modulo?
$b \mid a$ means there's $c$ such that $a = b c$. Then $-a = b (-c)$, so that $b \mid -a$.