Is there a theorem that makes solving $$ n! \equiv x \mod m $$ knowing that both $n$ and $m$ are prime?
And if not, what would be the best way to go about finding $x$?
cheers
Is there a theorem that makes solving $$ n! \equiv x \mod m $$ knowing that both $n$ and $m$ are prime?
And if not, what would be the best way to go about finding $x$?
cheers
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