Monty Hall Problem. If contestant choose door with goat and host reveal it....

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I need to confirm this scenario.

1 - The contestant picks a door with a goat behind it.

2 - The host opens this door and reveals the goat.

3 - The host gives the contestant the chance to pick a new door from the two remaining ones.

4 - contestant picks a new door.

5 - The classic scenario. Do you change the door or stay in the same door?

The probability is the same as the original problem (2/3)?

Cheers.

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If I understand this correctly, the host opens the door that the contestant had chosen initially and reveals it to contain a goat ... after which the contestant picks one of the other two doors ... after which the contestant is given a chance to switch?

If so, it's just 50-50: what we know about the two remaining doors is completely symmetrical, and the prize has to be behind one of them.