A matrix $A$ is idempotent if:
$$AA = A$$
Is it true that all such matrices are symmetric?
No. Here's a simple $2 x 2$ counterexample:
Define:
$$A = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix}$$
Note that $A$ is not symmetric, i.e. $$A^T = \begin{pmatrix} 1 &1\\0 &0 \end{pmatrix} \neq A$$
However, $A$ is idempotent:
$$AA = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} = A$$
Therefore, it cannot be the case that an idempotent matrix has to be symmetric.
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No. Here's a simple $2 x 2$ counterexample:
Define:
$$A = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix}$$
Note that $A$ is not symmetric, i.e. $$A^T = \begin{pmatrix} 1 &1\\0 &0 \end{pmatrix} \neq A$$
However, $A$ is idempotent:
$$AA = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} = \begin{pmatrix} 1 &0\\1 &0 \end{pmatrix} = A$$
Therefore, it cannot be the case that an idempotent matrix has to be symmetric.