Must an inverse of an inner product preserving operator be inner product preserving in an infinite dimensional space?

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According to my reasoning it must, because of the following argument:

Let $f:V\to V$ be an invertible inner product preserving linear operator, and let $g=f^{-1}$. Hence, $$ <g(u)|g(w)>\ =\ <f(g(u))|f(g(w))>\ =\ <u|w> $$ for any $u,w\in V$.

For some reason, in any source I found, the claim in the title was preceded by the assumption that $V$ is finite dimensional, so I wanted to make sure that there isn't any flaw in the very simple argument above.