In Peter office there are $N$ doors. Behind each door except one hides a doll. Lucy know what is behind each door while Peter does not. Peter has to select a door and wins if there is no doll behind it. Peter selects a door, instead of opening that door, Lucy opens $k$ other doors behind each of which is a doll , with $1\le k\le N-2$. Now Peter is given a choice to switch the door.
- What is the probability for Peter to win if Peter does not switch his initial choice?
- probability if he switch his initial choice
- prove that whatever are values of $N$ and $k$ , Peter should always switch doors.
Initial selection win probability is $\frac{1}{N}$. What happens after that doesn't effect result of initial selection. Win probability if he switches is then $\frac{N-1}{N}\times\frac{1}{(N-1-k)}$.