$n^{th}$ derivative of a hypergeometric function with a second order argument

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I know that:

\begin{equation} \dfrac{d^n}{dz^n} {_1 F_1}(a;b;z) = \dfrac{{(a)_n}}{{(b)_n}}{_1 F_1}(a+n;b+n;z). \end{equation}

Now what if I have, ${_1 F_1}(a;b;c x^2)$, what is

\begin{equation} \dfrac{d^n}{dx^n} {_1 F_1}(a;b;c x^2) \end{equation}

Thanks in advance.