if $2^7 \equiv 2 \mod n$ and $3^7 \equiv 3 \mod n$, then $a^7 \equiv a \mod n$.
I know Chines remainder and Eulers theorem but can't figure out how to proof this.
if $2^7 \equiv 2 \mod n$ and $3^7 \equiv 3 \mod n$, then $a^7 \equiv a \mod n$.
I know Chines remainder and Eulers theorem but can't figure out how to proof this.
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