A cylindrical tank has a diameter of $60 cm$ and a height of $100 cm$. It is filled with water to a depth of $10 cm$, then tilted by an angle $\theta = 30^\circ$. What will be the new depth of water? i.e. how high above the ground is the water surface in the tilted tank?
My Approach:
By taking horizontal slices of the water volume in the tilted tank, and integrating them to find the volume as a function of a set value $h$, and then iterating through Newton's iteration, I found that $h = 23.18cm$
Is there is a simpler or more direct way to solve this problem ?
