So I have a 3D line: $(0, 0, 0)+t(3, 4, 7)$
and I'm trying to find the normal of this. I know the gradient of the normal would normally be $\frac{-1}{\text{gradient}}$ but I'm not sure how you would find the gradient with 3 dimensions.
Any help would be much appreciated!
A line in 3D has a normal plane, which is here for instance spanned by the vectors (4,-3,0) and (1,1,-1). Therefore, there is no "the" normal vector. Please provide more context.