When one writes $C([0,1]; \mathbb{R}^d)$, they mean the following, right?
$C([0,1]; \mathbb{R}^d) \equiv \{f: [0,1] \rightarrow \mathbb{R}^d : f \text{ is continuous}\}$
I apologize for the stupidity of this question.
When one writes $C([0,1]; \mathbb{R}^d)$, they mean the following, right?
$C([0,1]; \mathbb{R}^d) \equiv \{f: [0,1] \rightarrow \mathbb{R}^d : f \text{ is continuous}\}$
I apologize for the stupidity of this question.
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Yes. But while I'm here I'll add that people usually are referring to the set as well as the supremum-norm when they use this notation.