I have this integral: $\int(\epsilon \wedge \|x\|^{2})\nu(dx)$
The $\wedge$ symbol means that I have to integrate $\|x\|^{2}$ when $\|x\|>\epsilon$ or when $\|x\|>1$?
I have this integral: $\int(\epsilon \wedge \|x\|^{2})\nu(dx)$
The $\wedge$ symbol means that I have to integrate $\|x\|^{2}$ when $\|x\|>\epsilon$ or when $\|x\|>1$?
Copyright © 2021 JogjaFile Inc.
The wedge stands for minimum. $a\wedge b=\min\{a,b\}$. The integral is $\int_{\{\|x||^{2} \geq \epsilon\}} \epsilon \nu (dx)+\int_{\{\|x||^{2} < \epsilon\}} \|x\|^{2} \nu (dx)$.