Number of characters for a finite group of order 57

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So this is an old prelim question and I have some questions. Let me first state the pre lim problem. If $G$ is a nonabelian group of order 57 how many 1-dimensional characters does $G$ have.

Now I know that up to isomorphism there is only one such group $G$ which can be realized as a semi direct product of $Z_{19}$ and $Z_3$. My question is regarding the definition of character. I've seen it defined as maps from $G\rightarrow \mathbb{C}^\times$ or generally to maps $G\rightarrow F$ where $F$ is a field, which is the correct definition? If its the first case how do I count such maps. Sorry I'm unfamiliar with representation/character theory, so assume that I'm completely uninformed on this matter. I was thinking of defining the maps into $\mathbb{C}^\times$ on $Z_{19}$ and $Z_3$ separately and combing them somehow, but now sure of my constructions. There's probably some theorems/lemmas from representation theory that would make this easier, but again I'm not familiar with them. Any help would be appreciated.

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For counting (complex) linear characters, you don't even have to construct them all. A standard result in character theory, see for instance Isaacs (1994, Corollary 2.23), says that such number equals the index of the commutator subgroup $\lvert G : G' \rvert$. Hence it equals three, as you've already know.